Harrison is the affected individual and has Maple Syrup Urine Disease. He has three siblings. His brother Jack and 2 sisters Abby, and Katie. Their parents are Allison and Mark. Mark has 2 sisters, Miranda and Chelsey. His parents are Ms. Shapiro and Mr. Shapiro. Allison has a sister Rachel and their parents are Mr. and Ms. O’Donald.
Harrison inherited this disease through the inheritance of 2 homozygous recessive genes that code for the disease. The only possible way for this to happen is if Harrison’s parents are carriers or affected. Neither parent is affected and therefore they both have to be carriers for Harrison to be born with the disease. If one was a carrier and the other was homozygous dominant then all children would have 50% chance of being carriers and 50% chance of being healthy. Therefore, the only combination in which parents can have a child with MSUD, but not have the disease is if they are both carriers.
If you have MSUD and follow the prescribed diet you can have children. However, it would be wise to have children with an individual who is homozygous dominant so none of your children will inherit the disease and they will just be carriers. There is a 100% chance that your children will not have the disease and just be carriers in that instance. However, if you have children with an individual who is a carrier, Rr, and you are RR then there is a 50% chance of the child being affected and a 50% chance of the child being a carrier. You should seek the help from a genetic counselor in that case.
In Allison and Mark’s case, based on their genotypes, 50% of their children would be carriers, 25% affected, and 25% nothing. Since they had four kids, and Harrison was affected, 2 of the children, based on probability, should be carriers, and 1 should be nothing. The parents also know that none of their other children were affected because they took a test as soon as they were born. The sibling who is neither a carrier nor affected cannot have an affected child, regardless of whom they mate with. The two carriers can have an affected child if they mate with an affected individual or carrier. To prove this you must use a punnett square to determine the outcome.
PUNNET SQUARES
| R | r |
R | RR | Rr |
r | Rr | rr |
Children of Allison and Mark
| R | R |
r | Rr | Rr |
r | Rr | Rr |
If Harrison mates with a Homozygous Dominant individual all children are carriers but not affected
| R | r |
r | Rr | rr |
r | Rr | rr |
50% of children will be affected if he mates with heterozygous individual
| R | r |
R | RR | Rr |
R | RR | Rr |
The healthy child, who is not a carrier, has no chance of their children being affected
| R | R |
R | RR | RR |
r | Rr | Rr |
Carriers can have children who are 50% carriers and 50% healthy